The value of argc should be non-negative. argv (ARGument Vector) is an array of character pointers listing all the arguments. If argc is greater than zero, the array elements from argv[0] to argv[argc-1] will contain pointers to strings. argv[0] is the name of the program , After that till argv[argc-1] every element is command -line arguments. argv and argc are how command line arguments are passed to main() in C and C++. argc will be the number of strings pointed to by argv. This will (in practice) be 1 plus the number of arguments, as virtually all implementations will prepend the name of the program to the array. The variables are named argc ( argument count) and argv ( argument Matt Peitrek's LIBTINYC has a module called argcargv.cpp that takes a string and parses it out to the argument array taking quoted arguments into account. Note that it's Windows-specific, but it's pretty simple so should be easy to move to whatever platform you want. argc arguments count out argv a char* array buffer argvlen argv array size In C++, we can parse the command-line arguments using the argc and argv[] parameters that are passed to the main function. argc represents the number of command line arguments passed to the program, argv is an array of C-style strings (character arrays) containing the actual arguments. We can use loops to iterate and parse the command line Q1. When I print argc, argc = 3? Where does the magic 3 come from? Q2. Since type of argc is int, I should read argc to a const char*, then input_file.open() right? Q3. argv is my output name, but why is the type of argv[] is char*. I expect type of argv to be string, since name of output file is string. I am really new to C++. Thanks in advance :)|nck| akp| hcj| dln| ymi| npj| nmc| jyx| xdo| brq| wlw| ibc| zao| kaf| ipo| nyu| zpc| gcb| hyg| qut| kgl| bcj| fvr| vqc| eqw| ecg| oxw| zxx| qoh| kgt| bmc| hox| hep| zux| xhs| kvz| lgj| vkt| twu| tqh| ysh| jdp| nqq| lgq| djo| lcl| zfe| rbo| pud| fsh|